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Question Number 175976 by rexford last updated on 10/Sep/22

Commented by Rasheed.Sindhi last updated on 10/Sep/22

$$Notclearenough.$$

Answered by floor(10²Eta[1]) last updated on 10/Sep/22

$${\mathrm{x}}^4={\mathrm{x}}^4{\mathrm{k}}_4+({4\mathrm{k}}_4+{\mathrm{k}}_3){\mathrm{x}}^3+({6\mathrm{k}}_4+{3\mathrm{k}}_3+{\mathrm{k}}_2){\mathrm{x}}^2+({4\mathrm{k}}_4+{3\mathrm{k}}_3+{2\mathrm{k}}_2+{\mathrm{k}}_1)\mathrm{x}+{\mathrm{k}}_4+{\mathrm{k}}_3+{\mathrm{k}}_2+{\mathrm{k}}_1+{\mathrm{k}}_0$$$$\Rightarrow {\mathrm{k}}_4=1,{4\mathrm{k}}_4+{\mathrm{k}}_3=0\Rightarrow {\mathrm{k}}_3=-4$$$$$$

Commented by rexford last updated on 11/Sep/22

$$igetit$$$$thankyouverymuchforyourtime$$

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