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Question Number 175995 by sciencestudent last updated on 10/Sep/22

$$li\underset{x\to 0}{m}\frac{e^{3x}-1}{x}=?$$

Answered by Ar Brandon last updated on 10/Sep/22

$$\underset{x\to 0}{\lim }\frac{e^{3x}-1}{x}=\underset{x\to 0}{\lim }\frac{(1+3x)-1}{x}=3$$

Answered by riyaziyyatelmlerinsahi last updated on 10/Sep/22

$$Answer:IbrahimAbdullayev$$$$\underset{x\to 0}{\lim }\frac{e^{3x}-1}{x}=\underset{x\to 0}{\lim }\frac{{(e^{3x}-1)}^{\prime }}{x^{\prime }}=\underset{x\to 0}{\lim }\frac{3e^{3x}}{1}=3\cdot \underset{x\to 0}{\lim }{e}^{3x}=3\cdot 1=3.$$

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