Question and Answers Forum

All Questions      Topic List

Algebra Questions

Previous in All Question      Next in All Question      

Previous in Algebra      Next in Algebra      

Question Number 176037 by Shrinava last updated on 11/Sep/22

If   (a−b)(a + b) = 13  Find   2a + b = ?

$$\mathrm{If}\:\:\:\left(\mathrm{a}−\mathrm{b}\right)\left(\mathrm{a}\:+\:\mathrm{b}\right)\:=\:\mathrm{13} \\ $$$$\mathrm{Find}\:\:\:\mathrm{2a}\:+\:\mathrm{b}\:=\:? \\ $$

Commented by Rasheed.Sindhi last updated on 11/Sep/22

20

$$\mathrm{20} \\ $$

Answered by Rasheed.Sindhi last updated on 11/Sep/22

Assuming a,b∈Z  (a−b)(a + b) =1× 13=−1×−13   { ((a−b=1)),((a+b=13)) :}⇒a=7,b=6  2a+b=2(7)+6=20  OR   { ((a−b=13)),((a+b=1)) :}⇒a=7,b=−6  2a+b=2(7)+(−6)=8    (a−b)(a + b) =−1×−13   { ((a−b=−1)),((a+b=−13)) :}⇒a=−7,b=−6  2a+b=2(−7)+(−6)=−20  OR   { ((a−b=−13)),((a+b=−1)) :}⇒a=−7,b=6  2a+b=2(−7)+6=−8

$$\mathrm{Assuming}\:\mathrm{a},\mathrm{b}\in\mathbb{Z} \\ $$$$\left(\mathrm{a}−\mathrm{b}\right)\left(\mathrm{a}\:+\:\mathrm{b}\right)\:=\mathrm{1}×\:\mathrm{13}=−\mathrm{1}×−\mathrm{13} \\ $$$$\begin{cases}{\mathrm{a}−\mathrm{b}=\mathrm{1}}\\{\mathrm{a}+\mathrm{b}=\mathrm{13}}\end{cases}\Rightarrow\mathrm{a}=\mathrm{7},\mathrm{b}=\mathrm{6} \\ $$$$\mathrm{2a}+\mathrm{b}=\mathrm{2}\left(\mathrm{7}\right)+\mathrm{6}=\mathrm{20} \\ $$$$\mathrm{OR} \\ $$$$\begin{cases}{\mathrm{a}−\mathrm{b}=\mathrm{13}}\\{\mathrm{a}+\mathrm{b}=\mathrm{1}}\end{cases}\Rightarrow\mathrm{a}=\mathrm{7},\mathrm{b}=−\mathrm{6} \\ $$$$\mathrm{2a}+\mathrm{b}=\mathrm{2}\left(\mathrm{7}\right)+\left(−\mathrm{6}\right)=\mathrm{8} \\ $$$$ \\ $$$$\left(\mathrm{a}−\mathrm{b}\right)\left(\mathrm{a}\:+\:\mathrm{b}\right)\:=−\mathrm{1}×−\mathrm{13} \\ $$$$\begin{cases}{\mathrm{a}−\mathrm{b}=−\mathrm{1}}\\{\mathrm{a}+\mathrm{b}=−\mathrm{13}}\end{cases}\Rightarrow\mathrm{a}=−\mathrm{7},\mathrm{b}=−\mathrm{6} \\ $$$$\mathrm{2a}+\mathrm{b}=\mathrm{2}\left(−\mathrm{7}\right)+\left(−\mathrm{6}\right)=−\mathrm{20} \\ $$$$\mathrm{OR} \\ $$$$\begin{cases}{\mathrm{a}−\mathrm{b}=−\mathrm{13}}\\{\mathrm{a}+\mathrm{b}=−\mathrm{1}}\end{cases}\Rightarrow\mathrm{a}=−\mathrm{7},\mathrm{b}=\mathrm{6} \\ $$$$\mathrm{2a}+\mathrm{b}=\mathrm{2}\left(−\mathrm{7}\right)+\mathrm{6}=−\mathrm{8} \\ $$$$ \\ $$

Commented by Shrinava last updated on 11/Sep/22

a,b∈N

$$\mathrm{a},\mathrm{b}\in\mathbb{N} \\ $$

Commented by Rasheed.Sindhi last updated on 11/Sep/22

If a,b∈N:  2a+b=2(7)+6=20

$$\mathrm{If}\:\mathrm{a},\mathrm{b}\in\mathbb{N}: \\ $$$$\mathrm{2a}+\mathrm{b}=\mathrm{2}\left(\mathrm{7}\right)+\mathrm{6}=\mathrm{20} \\ $$

Commented by Shrinava last updated on 11/Sep/22

cool thank you dear ser

$$\mathrm{cool}\:\mathrm{thank}\:\mathrm{you}\:\mathrm{dear}\:\mathrm{ser} \\ $$

Answered by BaliramKumar last updated on 11/Sep/22

a, b ∈ N  (a−b)(a+b) = 1×13  a−b = 1  a+b = 13  a = 7,     b = 6  2a+b = 2∙7 + 6 = 14 + 6 = 20 Answer    ••▶ a, b ∈ Z  (a, b) = (7, 6),  (−7, −6),  (7, −6),  (−7, 6)  2a + b = 20,  −20,     8,  −8  Answers    ••▶ a, b ∈ R  ∞ solutions

$${a},\:{b}\:\in\:\mathbb{N} \\ $$$$\left({a}−{b}\right)\left({a}+{b}\right)\:=\:\mathrm{1}×\mathrm{13} \\ $$$${a}−{b}\:=\:\mathrm{1} \\ $$$${a}+{b}\:=\:\mathrm{13} \\ $$$${a}\:=\:\mathrm{7},\:\:\:\:\:{b}\:=\:\mathrm{6} \\ $$$$\mathrm{2}{a}+{b}\:=\:\mathrm{2}\centerdot\mathrm{7}\:+\:\mathrm{6}\:=\:\mathrm{14}\:+\:\mathrm{6}\:=\:\mathrm{20}\:\mathrm{Answer} \\ $$$$ \\ $$$$\bullet\bullet\blacktriangleright\:{a},\:{b}\:\in\:\mathbb{Z} \\ $$$$\left({a},\:{b}\right)\:=\:\left(\mathrm{7},\:\mathrm{6}\right),\:\:\left(−\mathrm{7},\:−\mathrm{6}\right),\:\:\left(\mathrm{7},\:−\mathrm{6}\right),\:\:\left(−\mathrm{7},\:\mathrm{6}\right) \\ $$$$\mathrm{2}{a}\:+\:{b}\:=\:\mathrm{20},\:\:−\mathrm{20},\:\:\:\:\:\mathrm{8},\:\:−\mathrm{8}\:\:\mathrm{Answers} \\ $$$$ \\ $$$$\bullet\bullet\blacktriangleright\:{a},\:{b}\:\in\:\mathbb{R} \\ $$$$\infty\:{solutions} \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$

Commented by Shrinava last updated on 11/Sep/22

thank you dear ser

$$\mathrm{thank}\:\mathrm{you}\:\mathrm{dear}\:\mathrm{ser} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com