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Question Number 176133 by cortano1 last updated on 13/Sep/22

  Ω = ∫ ((−7x^2 +3x−8)/(4x^3 +8x^2 −20x−24)) dx

$$\:\:\Omega\:=\:\int\:\frac{−\mathrm{7x}^{\mathrm{2}} +\mathrm{3x}−\mathrm{8}}{\mathrm{4x}^{\mathrm{3}} +\mathrm{8x}^{\mathrm{2}} −\mathrm{20x}−\mathrm{24}}\:\mathrm{dx} \\ $$

Answered by kapoorshah last updated on 13/Sep/22

Ω =  −2ln ∣x + 3∣ + (3/4)ln ∣x + 1∣ −(1/2)ln ∣x − 2∣ + c

$$\Omega\:=\:\:−\mathrm{2ln}\:\mid{x}\:+\:\mathrm{3}\mid\:+\:\frac{\mathrm{3}}{\mathrm{4}}\mathrm{ln}\:\mid{x}\:+\:\mathrm{1}\mid\:−\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}\:\mid{x}\:−\:\mathrm{2}\mid\:+\:{c} \\ $$

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