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Question Number 176354 by BaliramKumar last updated on 16/Sep/22

Answered by Frix last updated on 16/Sep/22

in △ with sides a, b, c  r=((√((a+b+c)(−a+b+c)(a−b+c)(a+b−c)))/(2(a+b+c)))  in this case r=15

inwithsidesa,b,cr=(a+b+c)(a+b+c)(ab+c)(a+bc)2(a+b+c)inthiscaser=15

Commented by BaliramKumar last updated on 16/Sep/22

thanks

thanks

Answered by behi834171 last updated on 16/Sep/22

p=((51+52+53)/2)=((156)/2)=78  S=(√(78×27×26×25))=1170  r=(S/p)=((1170)/(78))=15  or:  S=(1/2)×r×51+(1/2)×r×52+(1/2)×r×53  ⇒1170=(1/2)r×156⇒r=15 . ■

p=51+52+532=1562=78S=78×27×26×25=1170r=Sp=117078=15or:S=12×r×51+12×r×52+12×r×531170=12r×156r=15.

Commented by BaliramKumar last updated on 16/Sep/22

thanks

thanks

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