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Question Number 176448 by peter frank last updated on 19/Sep/22

$$\mathrm{Suppose}{\mathrm{a}}^3+{\mathrm{b}}^3+{\mathrm{c}}^3={\mathrm{a}}^2+{\mathrm{b}}^2+{\mathrm{c}}^2$$$$=\mathrm{a}+\mathrm{b}+\mathrm{c}\mathrm{Prove}\mathrm{that}\mathrm{abc}=0$$$$$$

Commented by mr W last updated on 19/Sep/22

$$you{can}^{\prime }tprove!because{it}^{\prime }snottrue.$$$$examplea=b=c=1.$$

Commented by mr W last updated on 19/Sep/22

$$suppose$$$$a^3+b^3+c^3=a^2+b^2+c^2=a+b+c=k$$$$wecanget$$$$abc=\frac{k(k-1)(k-2)}{6}.$$

Commented by peter frank last updated on 19/Sep/22

$$\mathrm{thank}\mathrm{you}\mathrm{for}\mathrm{clarification}$$

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