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Question Number 176692 by mnjuly1970 last updated on 25/Sep/22

Commented by cortano1 last updated on 25/Sep/22

$$\mathrm{\Omega }=8{\pi }^4$$

Answered by blackmamba last updated on 25/Sep/22

$$\mathrm{\Omega }=\underset{x\to 0}{\lim }\frac{\sin {}^4\left(\pi \cos x\right)}{1-\cos (1-\cos \left(\frac{\sin {}^{2}x}{2}\right))}$$$$\mathrm{\Omega }=\underset{x\to 0}{\lim }\frac{\sin {}^4\left(\pi \cos x\right)}{1-\cos \left(\frac{\sin {}^2\left(\frac{\sin {}^{2}x}{2}\right)}{2}\right)}$$$$\mathrm{\Omega }=\underset{x\to 0}{\lim }\frac{\sin {}^4\left(\pi \cos x\right)}{\frac{\sin {}^2\left(\frac{\sin {}^2\left(\frac{\sin {}^{2}x}{2}\right)}{2}\right)}{2}}=\mathrm{\infty }$$

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