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Question Number 176716 by cortano1 last updated on 25/Sep/22

Answered by mr W last updated on 26/Sep/22

Commented by Tawa11 last updated on 26/Sep/22

$$\mathrm{Great}\mathrm{sir}$$

Commented by mr W last updated on 26/Sep/22

$$\beta +30°+\alpha +120°=180°$$$$\Rightarrow \beta =30°-\alpha$$$$\frac{\sin 2\alpha }{\sqrt{3}}=\frac{\sin \beta }{1}=\frac{\sin (30°-\alpha )}{1}$$$$\sin 2\alpha =\sqrt{3}\sin (30°-\alpha )$$$$\Rightarrow \alpha \approx 14.1328°\Rightarrow \mathrm{\angle }ABC\approx 45.8672°$$

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