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Question Number 176812 by mathlove last updated on 27/Sep/22

$$tan(a-b)=xandtan(a+b)=y$$$$thentan2\alpha =?$$

Commented by cortano1 last updated on 27/Sep/22

$$\tan 2a=?$$

Answered by cortano1 last updated on 27/Sep/22

$$2a=(a+b)+(a-b)$$$$\tan 2a=\frac{\tan (a+b)+\tan (a-b)}{1-\tan (a+b)\tan (a-b)}$$$$=\frac{x+y}{1-xy}$$

Commented by peter frank last updated on 27/Sep/22

$$\mathrm{good}$$

Commented by mathlove last updated on 27/Sep/22

$$thanks$$

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