Question and Answers Forum

All Questions      Topic List

Mensuration Questions

Previous in All Question      Next in All Question      

Previous in Mensuration      Next in Mensuration      

Question Number 176821 by Ar Brandon last updated on 27/Sep/22

Commented by som(math1967) last updated on 27/Sep/22

$$\frac{AF}{AL}=\frac{\frac{BC}{2}+CE+\frac{EK}{2}}{\frac{BC}{2}+CE+EK+\frac{KM}{2}}$$$$=\frac{.5+2+2}{.5+2+4+8}=\frac{4.5}{14.5}=\frac{9}{29}$$

Commented by Ar Brandon last updated on 27/Sep/22

Thank you Sir

Terms of Service

Privacy Policy

Contact: info@tinkutara.com