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Question Number 176888 by mr W last updated on 27/Sep/22

Commented by mr W last updated on 27/Sep/22

$a b a l l i s p r o j e c t e d f r o m p o i n t A o n t h e$ $g r o u n d a g a i n s t a w a l l a s s h o w n a n d$ $h i t s t h e w a l l a t p o i n t B .$ $i f t h e c o e f f i c i e n t o f r e s t i t u t i o n i s e,$ $f i n d t h e p o s i t i o n o f p o i n t C w h e r e$ $t h e b a l l h i t s t h e g r o u n d a g a i n .$ $(b, u, θ, φ, e a r e g i v e n)$
Commented by mr W last updated on 27/Sep/22

$n i c e y o u t u b e v i d e o s i r! i w i s h y o u$ $m u c h s u c c e s s w i t h y o u r c h a n n e l!$
Commented by ajfour last updated on 27/Sep/22
https://youtu.be/Ix0JqOQR_0g
	Answered by mr W last updated on 28/Sep/22

	Commented by mr W last updated on 29/Sep/22

	$t h e c o l l i s i o n w i t h t h e w a l l {d o e s n}^{'} t$ $a f f e c t t h e m o t i o n o f t h e b a l l i n t h e$ $Y - a n d Z - d i r e c t i o n .$ $t o t a l f l i g h t t i m e o f t h e b a l l i n t h e a i r$ $i s t = \frac{2 u \sin θ}{g} .$ $t h e d i s t a n c e t h e b a l l t r a v e l e d i n t h i s$ $t i m e i n Y - d i r e c t i o n i s$ $y_{C} = u \cos θ \sin φ \times \frac{2 u \sin θ}{g}$ $\Rightarrow y_{C} = \frac{u^{2} \sin 2 θ \sin φ}{g}$ $b e f o r e t h e c o l l i s i o n w i t h t h e w a l l t h e$ $b a l l m o v e d i n X - d i r e c t i o n w i t h s p e e d$ $v_{x, i} = u \cos θ \cos φ$ $a f t e r t h e c o l l i s i o n i t s s p e e d$ $i n X - d i r e c t i o n i s$ $v_{x, f} = e v_{x, i} = e u \cos θ \cos φ$ $\frac{b}{v_{x, i}} + \frac{x_{C}}{v_{x, f}} = t$ $x_{C} = e ({t v}_{x, i} - b)$ $x_{C} = e (\frac{2 u \sin θ}{g} \times u \cos θ \cos φ - b)$ $\Rightarrow x_{C} = e (\frac{u^{2} \sin 2 θ \cos φ}{g} - b)$
	Commented by Tawa11 last updated on 03/Oct/22

	$Great sir$
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