Question and Answers Forum

All Questions      Topic List

Mensuration Questions

Previous in All Question      Next in All Question      

Previous in Mensuration      Next in Mensuration      

Question Number 176942 by Ar Brandon last updated on 28/Sep/22

Answered by som(math1967) last updated on 28/Sep/22

$$HE=GF=\frac{1}{2}\times AC=\frac{17}{2}cm$$$$EF=HG=\frac{1}{2}\times DB=\frac{13}{2}cm$$$$perimeterEFGH=2(\frac{17}{2}+\frac{13}{2})$$$$=30cm$$

Commented by Ar Brandon last updated on 28/Sep/22

Thank you, Sir

Terms of Service

Privacy Policy

Contact: info@tinkutara.com