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Question Number 177008 by Ar Brandon last updated on 29/Sep/22

Answered by Rasheed.Sindhi last updated on 29/Sep/22

$$Lettistotalofcardnumberschosebyplayers.$$$${Efe}^{\prime }scardnumber=3$$$$6⩽t⩽20$$$$Ift\in \mathbb{P}thenpossiblevaluesfort:$$$$t=7,11,13,17,19$$$$totalofother{two}^{\prime }s:$$$$t-3=4,8,10,14,16$$$$Pairsofothertwo:$$$$\begin{array}{|cc|}\hline t-3& possiblepairs\\ 4& -\\ 8& (1,7),(2,6),(6,2),(7,1)\\ 10& (1,9),(2,8),(4,6),(6,4),(8,2),(9,1)\\ 14& (5,9),(6,8),(8,6),(9,5)\\ 16& (7,9),(9,7)\\ \hline\end{array}$$$$\mathcal{T}otalpossiblepairsforothertwo:$$$$8\times 7=56$$$$\mathcal{N}umberofpairswhenEfewins=16$$$$probabilitytowinEfe:$$$$=\frac{16}{56}=\frac{2}{7}$$

Commented by Ar Brandon last updated on 29/Sep/22

$$\mathrm{Thank}\mathrm{you},\mathrm{Sir}!$$

Commented by Tawa11 last updated on 02/Oct/22

$$\mathrm{Great}\mathrm{sir}$$

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