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Question Number 177013 by mr W last updated on 29/Sep/22

Commented by mr W last updated on 29/Sep/22

$$findtheareaofthesector.$$

Answered by Rasheed.Sindhi last updated on 29/Sep/22

$$\mathcal{T}hediameter=\sqrt{4^2+{(3+5)}^2}=4\sqrt{5}$$$$Rsdius=2\sqrt{5}$$$$Areaofcircle=\pi {\left(2\sqrt{5}\right)}^2=20\pi$$$$Areaofsector=\frac{20\pi }{4}=5\pi$$

Commented by mr W last updated on 29/Sep/22

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Commented by Rasheed.Sindhi last updated on 29/Sep/22

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Commented by mr W last updated on 29/Sep/22

Commented by Rasheed.Sindhi last updated on 29/Sep/22

$$\mathbb{T}\mathbf{han}\mathbb{k}\mathbf{s}\mathrm{for}\mathrm{diagram}\mathbf{sir}!$$🙏🌷🌹🙏

Commented by mr W last updated on 30/Sep/22

$$thanksforsmartsolutionsir!$$

Commented by Tawa11 last updated on 02/Oct/22

$$\mathrm{Great}\mathrm{sirs}$$

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