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Question Number 177132 by mokys last updated on 01/Oct/22

Commented by mr W last updated on 01/Oct/22

instead of posting these ?????, you  can easily try by yourself:  A=(−(1/3))(−(3/5))(−(5/7))...(−((4k−1)/(4k+1)))  =(−1)^(2k) (1/(4k+1))  =(1/(4k+1)) ✓

$${instead}\:{of}\:{posting}\:{these}\:?????,\:{you} \\ $$$${can}\:{easily}\:{try}\:{by}\:{yourself}: \\ $$$${A}=\left(−\frac{\mathrm{1}}{\cancel{\mathrm{3}}}\right)\left(−\frac{\cancel{\mathrm{3}}}{\cancel{\mathrm{5}}}\right)\left(−\frac{\cancel{\mathrm{5}}}{\cancel{\mathrm{7}}}\right)...\left(−\frac{\cancel{\mathrm{4}{k}−\mathrm{1}}}{\mathrm{4}{k}+\mathrm{1}}\right) \\ $$$$=\left(−\mathrm{1}\right)^{\mathrm{2}{k}} \frac{\mathrm{1}}{\mathrm{4}{k}+\mathrm{1}} \\ $$$$=\frac{\mathrm{1}}{\mathrm{4}{k}+\mathrm{1}}\:\checkmark \\ $$

Commented by mokys last updated on 01/Oct/22

???????

$$??????? \\ $$

Commented by Tawa11 last updated on 02/Oct/22

Great sir

$$\mathrm{Great}\:\mathrm{sir} \\ $$

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