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Question Number 177132 by mokys last updated on 01/Oct/22

Commented by mr W last updated on 01/Oct/22

$$insteadofpostingthese?????,you$$$$caneasilytrybyyourself:$$$$A=(-\frac{1}{\cancel{3}})(-\frac{\cancel{3}}{\cancel{5}})(-\frac{\cancel{5}}{\cancel{7}})...(-\frac{\cancel{4k-1}}{4k+1})$$$$={(-1)}^{2k}\frac{1}{4k+1}$$$$=\frac{1}{4k+1}✓$$

Commented by mokys last updated on 01/Oct/22

$$???????$$

Commented by Tawa11 last updated on 02/Oct/22

$$\mathrm{Great}\mathrm{sir}$$

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