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Question Number 177560 by aurpeyz last updated on 07/Oct/22

Commented by aurpeyz last updated on 07/Oct/22

$T h a n k y o u S i r$
	Answered by Rasheed.Sindhi last updated on 07/Oct/22

	$L e t t h e b i g l i s t c o n t s i n s x d a t a i t e m s$ $A c o n t a i n s \frac{x}{2} i t e m s$ $∵ A v e r a g e o f A i s 12$ $∴ T h e t o t a l o f A i s 12 \times \frac{x}{2} = 6 x$ $B c o n t a i n s \frac{x}{5} i t e m s$ $∵ A v e r a g e o f B i s 15$ $∴ T h e t o t a l o f B i s 15 \times \frac{x}{5} = 3 x$ $C c o n t a i n s x - (\frac{x}{2} + \frac{x}{5}) = \frac{10 x - 5 x - 2 x}{10} = \frac{3 x}{10}$ $∵ A v e r a g e o f C i s 6$ $∴ T h e t o t a l o f C i s 6 \times \frac{3 x}{10} = \frac{9 x}{5}$ $T h e t o t a l o f b i g l i s t i s$ $6 x + 3 x + \frac{9 x}{5} = \frac{30 x + 15 x + 9 x}{5} = \frac{54 x}{5}$ $T h e a v e r a g e o f b i g l i s t = \frac{(54 x) / 5}{x}$ $= 10.8$
	Commented by aurpeyz last updated on 07/Oct/22

	$t h a n k s$
	Answered by Rasheed.Sindhi last updated on 07/Oct/22

	$L e t g r a n d l i s t c o n t a i n s 10 d a t a i t e m s$ $(A n u m b e r d i v i s i b l e b y 2 & 5)$ $A c o n t a i n s 5 i t e m s (H a l f o f 10)$ $T o t a l o f A = a v e r a g e \times n u m b e r o f i t e m s$ $= 12 \times 5 = 60$ $B c o n t a i n s 2 i t e m s (O n e - f i f t h o f 10)$ $T o t a l o f B = 15 \times 2 = 30$ $C c o n t a i n s 10 - (5 + 2) = 3 i t e m s$ $T o t a l o f C = 6 \times 3 = 18 i t e m s$ $T o t a l o f g r a n d l i s t = 60 + 30 + 18 = 108$ $A v e r a g e o f g r a n d l i s t = \frac{108}{10} = 10.8$
	Commented by aurpeyz last updated on 07/Oct/22

	$t h a n k s$
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