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Question Number 177725 by Spillover last updated on 08/Oct/22

$$\mathrm{Find}\mathrm{the}\mathrm{oxidation}\mathrm{number}\mathrm{of}\mathrm{the}$$$$\mathrm{underlined}\mathrm{element}\mathrm{in}\mathrm{the}$$$$\mathrm{following}$$$$\left(\mathrm{a}\right)\mathrm{K}\underset{―}{\mathbf{Cl}}{\mathrm{O}}_3$$$$\left(\mathrm{b}\right){\underset{―}{\mathrm{S}O}}_3^{2-}$$$$\left(\mathrm{c}\right){\mathrm{H}}_2{\underset{―}{\mathrm{S}O}}_4$$$$\left(\mathrm{d}\right)\underset{―}{\mathrm{Na}}\mathrm{H}$$$$$$

Commented by Tawa11 last updated on 08/Oct/22

$$\left(\mathrm{a}\right)1+\mathrm{x}-6=0$$$$\mathrm{x}-5=0$$$$\mathrm{x}=5[\mathrm{Cl}=5]$$$$$$$$\left(\mathrm{b}\right)\mathrm{x}-6=-2$$$$\mathrm{x}=-2+6$$$$\mathrm{x}=4[\mathrm{S}=4]$$$$$$$$\left(\mathrm{c}\right)2+\mathrm{x}-8=0$$$$\mathrm{x}-6=0$$$$\mathrm{x}=6[\mathrm{S}=6]$$$$$$$$\left(\mathrm{d}\right)\mathrm{x}-1=0$$$$\mathrm{x}=1[\mathrm{Na}=1]$$

Commented by Spillover last updated on 08/Oct/22

$$\mathrm{perfect}.$$

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