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Question Number 177763 by lapache last updated on 08/Oct/22
SolveinRthesystem{x+y=z1x+1y=1z
Commented by mr W last updated on 08/Oct/22
nosolutionforx,y,z∈R.x,yarerootsoft2−zt+z2=0,butthishasnorealroots,becauset2−zt+z2=(t−z2)2+3z24≠0forz≠0.
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