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Question Number 177796 by mr W last updated on 09/Oct/22

Commented by mr W last updated on 09/Oct/22

find the area of the square.

findtheareaofthesquare.

Commented by mr W last updated on 09/Oct/22

∠DFE=90°  side length of square should be unique.

DFE=90°sidelengthofsquareshouldbeunique.

Commented by Rasheed.Sindhi last updated on 09/Oct/22

You′re right sir!

Yourerightsir!

Commented by Rasheed.Sindhi last updated on 09/Oct/22

Sir I think that the area depends   upon BE or FC. In other words  the area of square is not unique.

SirIthinkthattheareadependsuponBEorFC.Inotherwordstheareaofsquareisnotunique.

Answered by mr W last updated on 09/Oct/22

BC=DC=s  ΔEBF∼ΔFCD  ((BF)/3)=(s/4) ⇒BF=((3s)/4)  FC=(√(4^2 −s^2 ))  BF+FC=s  ((3s)/4)+(√(4^2 −s^2 ))=s  ⇒s^2 =((16×16)/(17))=((256)/(17))=square′s area

BC=DC=sΔEBFΔFCDBF3=s4BF=3s4FC=42s2BF+FC=s3s4+42s2=ss2=16×1617=25617=squaresarea

Commented by Tawa11 last updated on 09/Oct/22

Great sirs

Greatsirs

Answered by cortano1 last updated on 09/Oct/22

AD=CD= d   BF=a , CF=b⇒d=a+b  AE=c , BE=f⇒d=c+f    { ((c^2 +d^2 =25)),((d^2 +b^2 =16)),((a^2 +f^2 =9)) :}    ⇒a=(3/( (√(17)))) ; b=((12)/( (√(17))))  ⇒c= (4/( (√(17)))) ; d=((16)/( (√(17)))) ; f=((13)/( (√(17))))  area of square = ((256)/(17))

AD=CD=dBF=a,CF=bd=a+bAE=c,BE=fd=c+f{c2+d2=25d2+b2=16a2+f2=9a=317;b=1217c=417;d=1617;f=1317areaofsquare=25617

Answered by cortano1 last updated on 09/Oct/22

((256)/(17)) ?

25617?

Commented by mr W last updated on 09/Oct/22

yes!

yes!

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