Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 177975 by aurpeyz last updated on 11/Oct/22

Answered by mr W last updated on 11/Oct/22

$$\mathrm{\angle }ACB=x/2$$$$\mathrm{\angle }BAC=y$$$$\mathrm{\angle }B=180-x/2-y$$$$\mathrm{\angle }ADC=180-\mathrm{\angle }B=x/2+y$$

Commented by Tawa11 last updated on 11/Oct/22

$$\mathrm{Great}\mathrm{sir}$$

Commented by aurpeyz last updated on 11/Oct/22

$$plshowis\mathrm{\angle }ACB=x/2.thatstheonlypart$$$$thatididntget.thanks$$

Commented by mr W last updated on 12/Oct/22

Commented by aurpeyz last updated on 12/Oct/22

$$thankssir$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com