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Question Number 178026 by aurpeyz last updated on 12/Oct/22

Commented by som(math1967) last updated on 12/Oct/22

46

$$\mathrm{46} \\ $$

Commented by aurpeyz last updated on 12/Oct/22

solution pls

$${solution}\:{pls} \\ $$

Answered by FelipeLz last updated on 12/Oct/22

CE = CD = 23 BF = BE AD = AF p_(ABC) = AB+BC+AC p_(ABC) = (AF+BF)+(CE−BE)+(CD−AD) p_(ABC) = AF+BF+CE−BE+CD−AD p_(ABC) = CE+CD = 46

$${CE}\:=\:{CD}\:=\:\mathrm{23} \\ $$$${BF}\:=\:{BE} \\ $$$${AD}\:=\:{AF} \\ $$$${p}_{{ABC}} \:=\:{AB}+{BC}+{AC}\: \\ $$$${p}_{{ABC}} \:=\:\left({AF}+{BF}\right)+\left({CE}−{BE}\right)+\left({CD}−{AD}\right) \\ $$$${p}_{{ABC}} \:=\:{AF}+{BF}+{CE}−{BE}+{CD}−{AD} \\ $$$${p}_{{ABC}} \:=\:{CE}+{CD}\:=\:\mathrm{46} \\ $$

Commented by Tawa11 last updated on 12/Oct/22

Great sir

$$\mathrm{Great}\:\mathrm{sir} \\ $$

Commented by aurpeyz last updated on 12/Oct/22

thanks

$${thanks} \\ $$

Commented by aurpeyz last updated on 12/Oct/22

Sir. what is the rule that makes CD=CE and BE=BF?

$${Sir}.\:{what}\:{is}\:{the}\:{rule}\:{that}\:{makes}\:{CD}={CE}\:{and}\:{BE}={BF}? \\ $$

Commented by aurpeyz last updated on 12/Oct/22

thanks so much

$${thanks}\:{so}\:{much} \\ $$

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