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Question Number 178103 by aurpeyz last updated on 12/Oct/22

A sample of 18 integers has an average   (arithemetic mean) equal to M and standard  deviation equal to S. Two of the integers  are equal to m.  Quantity A: The standard devuaition of  the 16 integers that are not equal to m.  Quantity B: S

$${A}\:{sample}\:{of}\:\mathrm{18}\:{integers}\:{has}\:{an}\:{average}\: \\ $$$$\left({arithemetic}\:{mean}\right)\:{equal}\:{to}\:{M}\:{and}\:{standard} \\ $$$${deviation}\:{equal}\:{to}\:{S}.\:{Two}\:{of}\:{the}\:{integers} \\ $$$${are}\:{equal}\:{to}\:{m}. \\ $$$${Quantity}\:{A}:\:{The}\:{standard}\:{devuaition}\:{of} \\ $$$${the}\:\mathrm{16}\:{integers}\:{that}\:{are}\:{not}\:{equal}\:{to}\:{m}. \\ $$$${Quantity}\:{B}:\:{S} \\ $$

Commented by aurpeyz last updated on 13/Oct/22

a. Quantity A is greater than B  b. Quantity B is greater than A  c. Quantity A and B are equal  e. cannot determined by the info

$${a}.\:{Quantity}\:{A}\:{is}\:{greater}\:{than}\:{B} \\ $$$${b}.\:{Quantity}\:{B}\:{is}\:{greater}\:{than}\:{A} \\ $$$${c}.\:{Quantity}\:{A}\:{and}\:{B}\:{are}\:{equal} \\ $$$${e}.\:{cannot}\:{determined}\:{by}\:{the}\:{info} \\ $$

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