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Question Number 178375 by doline last updated on 16/Oct/22

$$calculeruneprimitivede-3x/\sqrt{x^2+3}$$

Commented by CElcedricjunior last updated on 16/Oct/22

$$\int \frac{-3\mathbf{xdx}}{\sqrt{3+{\mathbf{x}}^2}}=-\frac{3}{2}\int \frac{2\mathit{x}}{\sqrt{3+{\mathit{x}}^2}}\mathit{d}\mathit{x}=-\frac{3}{2}\sqrt{3+{\mathit{x}}^2}+\mathit{K}$$$$\mathbf{k}\in \mathbb{R}$$

Answered by Ar Brandon last updated on 16/Oct/22

$$\int \frac{-3x}{\sqrt{x^2+3}}dx=-\frac{3}{2}\int \frac{2x}{\sqrt{x^2+3}}dx=-3\sqrt{x^2+3}+\mathrm{cst}$$

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