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Question Number 178388 by mathlove last updated on 16/Oct/22

p(sin^(77) ((50)/(19)),cos((27)/(13))) 1) VI 2)III 3)II 4)I

$$\:{p}\left({sin}^{\mathrm{77}} \frac{\mathrm{50}}{\mathrm{19}},{cos}\frac{\mathrm{27}}{\mathrm{13}}\right) \\ $$ $$\left.\mathrm{1}\left.\right)\left.\:\left.{VI}\:\:\:\:\mathrm{2}\right){III}\:\:\:\:\:\mathrm{3}\right){II}\:\:\:\:\:\:\:\mathrm{4}\right){I} \\ $$ In which region of the fixed coordinate system is this point located?\\n

Answered by saboorhalimi last updated on 16/Oct/22

p(+, −) ⇒ IV

$$\:{p}\left(+,\:−\right)\:\Rightarrow\:{IV}\: \\ $$

Commented bymathlove last updated on 16/Oct/22

pleas solve it

$${pleas}\:{solve}\:{it} \\ $$

Answered by mr W last updated on 16/Oct/22

((50)/(19))=((50π)/(19π))≈0.838π ∈((π/2), π) sin ((50)/(19))>0 ⇒sin^(77) ((50)/(19)) >0 ((27)/(13))=((27π)/(13π))≈0.661π ∈((π/2), π) cos ((27)/(13))<0 p(+,−) ⇒ IV

$$\frac{\mathrm{50}}{\mathrm{19}}=\frac{\mathrm{50}\pi}{\mathrm{19}\pi}\approx\mathrm{0}.\mathrm{838}\pi\:\in\left(\frac{\pi}{\mathrm{2}},\:\pi\right)\: \\ $$ $$\mathrm{sin}\:\frac{\mathrm{50}}{\mathrm{19}}>\mathrm{0}\:\Rightarrow\mathrm{sin}^{\mathrm{77}} \:\frac{\mathrm{50}}{\mathrm{19}}\:>\mathrm{0} \\ $$ $$ \\ $$ $$\frac{\mathrm{27}}{\mathrm{13}}=\frac{\mathrm{27}\pi}{\mathrm{13}\pi}\approx\mathrm{0}.\mathrm{661}\pi\:\in\left(\frac{\pi}{\mathrm{2}},\:\pi\right) \\ $$ $$\mathrm{cos}\:\frac{\mathrm{27}}{\mathrm{13}}<\mathrm{0} \\ $$ $$ \\ $$ $${p}\left(+,−\right)\:\Rightarrow\:{IV} \\ $$

Commented bymathlove last updated on 16/Oct/22

thanks a lot sir

$${thanks}\:{a}\:{lot}\:{sir} \\ $$

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