(2x^3 y+3xy−5x^2 y^2 +12)÷(2x−4)


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Question Number 178413 by mathlove last updated on 16/Oct/22

$(2 x^{3} y + 3 x y - 5 x^{2} y^{2} + 12) \div (2 x - 4)$ Divide it using compound division\n
Commented byRasheed.Sindhi last updated on 17/Oct/22

${W h a t}^{'} s m e a n t b y ♮ c o m p o u n d d i v i s i o n ε ?$
Commented bymathlove last updated on 18/Oct/22

$H a r n e r d i v a i d e d$
	Answered by Rasheed.Sindhi last updated on 18/Oct/22

	$(2 x^{3} y + 3 x y - 5 x^{2} y^{2} + 12) \div (2 x - 4)$ $= (x^{3} y - \frac{5}{2} x^{2} y^{2} + \frac{3}{2} x y + 6) \div (x - 2)$ $Extra close brace or missing open brace$ $f o r m x - α, w e^{'} v e d i v i d e d b o t h$ $Missing \left or extra \right$ $\begin{array}{ccc} 2) & y & - \frac{5}{2} y^{2} & \frac{3}{2} y & 6 \\ 2 y & - 5 y^{2} + 4 y & - 10 y^{2} + 11 y \\ y & - \frac{5}{2} y^{2} + 2 y & - 5 y^{2} + \frac{11}{2} y & - 10 y^{2} + 11 y + 6 \end{array}$ $x^{2} y + x (- \frac{5}{2} y^{2} + 2 y) - 5 y^{2} + \frac{11}{2} y + \frac{- 10 y^{2} + 11 y + 6}{x - 2} ◂ A n s$
	Commented bymathlove last updated on 18/Oct/22

	$t h a n k s a l o t m y t e a c h e r$
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