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Question Number 179066 by cortano1 last updated on 24/Oct/22
Iff(x)=∫x2x2+tanxdxthen∫tanxx2+tanxdx=?
Answered by Ar Brandon last updated on 24/Oct/22
f(x)=∫x2x2+tanxdx=∫(x2+tanx)−tanxx2+tanxdx=∫(1−tanxx2+tanx)dx=x−∫tanxx2+tanxdx⇒∫tanxx2+tanxdx=x−f(x)
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