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Question Number 179107 by Acem last updated on 25/Oct/22
I=∫x2sin(2arctan(ex))dx,FindI
Answered by MJS_new last updated on 25/Oct/22
∫x2sun2arctanexdx=∫x2coshxdx=[byparts]=x2sinhx−2∫xsinhxdx=[byparts]=x2sinhx−2xcoshx+2∫sinhxdx==x2sinhx−2xcoshx+2sinhx==(x2+2)sinhx−2xcoshx+C
Commented by Acem last updated on 25/Oct/22
Exactly!goodSir!
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