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Question Number 179496 by a.lgnaoui last updated on 29/Oct/22

$$Evaluer$$$${\int }_1^2\frac{\sin \left(\log \left(\mathrm{x}\right)\right)}{\mathrm{x}}\mathrm{dx}$$

Answered by ARUNG_Brandon_MBU last updated on 29/Oct/22

$${\int }_1^2\frac{\sin \left(\log x\right)}{x}dx$$$$={\int }_1^2\sin \left(\log x\right)d\left(\log x\right)$$$$={\left[\cos \left(\log x\right)\right]}_2^1=1-\cos \left(\log 2\right)$$

Commented by a.lgnaoui last updated on 30/Oct/22

$$thanks$$

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