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Question Number 179679 by ROOSEVELT last updated on 01/Nov/22

$${\int }_2^4\tan \left(x\right)$$

Answered by Acem last updated on 01/Nov/22

$$a=-\ln \mid \cos x\mid {\mid }_2^4=-\ln \mid \cos 4\mid +\ln \mid \cos 2\mid$$$$=18.29E{10}^{-4}$$

Commented by Frix last updated on 01/Nov/22

$$\mathrm{I}{\mathrm{don}}^{\prime }\mathrm{t}\mathrm{think}\mathrm{angles}\mathrm{are}\mathrm{in}\mathrm{degree}\mathrm{when}\mathrm{it}$$$$\mathrm{comes}\mathrm{to}\mathrm{integrals}$$$$-\ln \mid \cos 4\mid +\ln \mid \cos 2\mid \approx -.451524$$$$\mathrm{if}x\mathrm{is}\mathrm{in}\mathrm{degree}:$$$$\int \tan xdx=-\frac{180}{\pi }\ln \mid \cos x\mid$$$$\mathrm{and}\mathrm{the}\mathrm{answer}\mathrm{would}\mathrm{be}$$$$\underset{2°}{\stackrel{4°}{\int }}\tan xdx\approx .104826$$

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