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Question Number 179688 by Acem last updated on 01/Nov/22

Commented by HeferH last updated on 01/Nov/22

Commented by HeferH last updated on 01/Nov/22

φ=30°

ϕ=30°

Commented by CElcedricjunior last updated on 01/Nov/22

calculons ∅  d′apre^� s le theoreme des sinus  (x/(sin15))=(b/(sin(30)))=(k/(sin135))=>(b/x)=2cos15 (1)  (x/(sin∅))=(b/(sin45))=(m/(sin𝛀))=>(b/x)=((sin45)/(sin∅)) (2)  (1)=(2)  ⇔((sin45)/(sin∅))=2cos15  ⇔sin∅=((sin45)/(2cos15))=(2/(2(√2)((√((√3)+2)))))=(1/( (√(2(√3)+4))))  sin∅=((√(2(√3)+4))/(2(√2)+4))  =>∅=arsin(((√(2(√3)+4))/(2(√3)+4)))=21.47°  ..........le celebre cedric junior.............

calculonsdapre`sletheoremedessinusxsin15=bsin(30)=ksin135=>bx=2cos15(1)xsin=bsin45=msinΩ=>bx=sin45sin(2)(1)=(2)sin45sin=2cos15sin=sin452cos15=222(3+2)=123+4sin=23+422+4=>=arsin(23+423+4)=21.47°..........lecelebrecedricjunior.............

Commented by Acem last updated on 01/Nov/22

Sir HeferH, the same way of mine, thanks

SirHeferH,thesamewayofmine,thanks

Commented by Acem last updated on 01/Nov/22

Monsieur Junior, merci beaucoup,  mais l′angle est 30°

MonsieurJunior,mercibeaucoup,maislangleest30°

Answered by mr W last updated on 01/Nov/22

an other way    ((sin (45+φ))/(sin φ))=((sin (45−15))/(sin 15))  (1+(1/(tan φ)))(1/( (√2)))=(1/(2 sin 15))=(2/( (√6)−(√2)))  tan φ=(1/( (√3)))  ⇒φ=30°

anotherwaysin(45+ϕ)sinϕ=sin(4515)sin15(1+1tanϕ)12=12sin15=262tanϕ=13ϕ=30°

Commented by Acem last updated on 01/Nov/22

Good!

Good!

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