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Question Number 17976 by tawa tawa last updated on 13/Jul/17

A driver is 5.2 below the surface of water of density 1000kg/m.  if the  atmospheric pressure is 1.02 × 10^5  Pa. calculate the pressure on the driver.

$$\mathrm{A}\:\mathrm{driver}\:\mathrm{is}\:\mathrm{5}.\mathrm{2}\:\mathrm{below}\:\mathrm{the}\:\mathrm{surface}\:\mathrm{of}\:\mathrm{water}\:\mathrm{of}\:\mathrm{density}\:\mathrm{1000kg}/\mathrm{m}.\:\:\mathrm{if}\:\mathrm{the} \\ $$$$\mathrm{atmospheric}\:\mathrm{pressure}\:\mathrm{is}\:\mathrm{1}.\mathrm{02}\:×\:\mathrm{10}^{\mathrm{5}} \:\mathrm{Pa}.\:\mathrm{calculate}\:\mathrm{the}\:\mathrm{pressure}\:\mathrm{on}\:\mathrm{the}\:\mathrm{driver}. \\ $$

Answered by ajfour last updated on 13/Jul/17

P=P_0 +ρgh     =1.02×10^5 +10^3 ×9.8×5.2     =1.53×10^5  Pa .

$$\mathrm{P}=\mathrm{P}_{\mathrm{0}} +\rho\mathrm{gh} \\ $$$$\:\:\:=\mathrm{1}.\mathrm{02}×\mathrm{10}^{\mathrm{5}} +\mathrm{10}^{\mathrm{3}} ×\mathrm{9}.\mathrm{8}×\mathrm{5}.\mathrm{2} \\ $$$$\:\:\:=\mathrm{1}.\mathrm{53}×\mathrm{10}^{\mathrm{5}} \:\mathrm{Pa}\:. \\ $$

Commented by tawa tawa last updated on 13/Jul/17

God bless you sir.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

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