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Question Number 180200 by Acem last updated on 09/Nov/22

A) How many even numbers of 3 different digits   bigger than 300 can be formed from {1, 2, 3, 4}  B) How many numbers bigger than 300 can          be formed from the same group

$$\left.\boldsymbol{{A}}\right)\:{How}\:{many}\:{even}\:{numbers}\:{of}\:\mathrm{3}\:{different}\:{digits} \\ $$$$\:{bigger}\:{than}\:\mathrm{300}\:{can}\:{be}\:{formed}\:{from}\:\left\{\mathrm{1},\:\mathrm{2},\:\mathrm{3},\:\mathrm{4}\right\} \\ $$$$\left.\boldsymbol{{B}}\right)\:{How}\:{many}\:{numbers}\:{bigger}\:{than}\:\mathrm{300}\:{can} \\ $$$$\:\:\:\:\:\:\:\:{be}\:{formed}\:{from}\:{the}\:{same}\:{group} \\ $$

Commented by Frix last updated on 09/Nov/22

6

$$\mathrm{6} \\ $$

Commented by Acem last updated on 09/Nov/22

Right! thank you,  well, please, put the solution   method in answers part

$${Right}!\:{thank}\:{you},\:\:{well},\:{please},\:{put}\:{the}\:{solution} \\ $$$$\:{method}\:{in}\:{answers}\:{part} \\ $$

Answered by Acem last updated on 09/Nov/22

Commented by Acem last updated on 09/Nov/22

A) Num_(Numb.) = 6  B) Num_(Numb.) = 288  See Mr. W ′s note above

$$\left.{A}\right)\:{Num}_{{Numb}.} =\:\mathrm{6} \\ $$$$\left.{B}\right)\:{Num}_{{Numb}.} =\:\cancel{\mathrm{288}}\:\:{See}\:{Mr}.\:{W}\:'{s}\:{note}\:{above} \\ $$

Commented by Acem last updated on 09/Nov/22

And yes I agrre with Mr. W that there are infinite   numbers of infinite digits!

$${And}\:{yes}\:{I}\:{agrre}\:{with}\:{Mr}.\:{W}\:{that}\:{there}\:{are}\:{infinite} \\ $$$$\:{numbers}\:{of}\:{infinite}\:{digits}! \\ $$

Answered by Frix last updated on 09/Nov/22

312 314 324 342 412 432  6 numbers

$$\mathrm{312}\:\mathrm{314}\:\mathrm{324}\:\mathrm{342}\:\mathrm{412}\:\mathrm{432} \\ $$$$\mathrm{6}\:\mathrm{numbers} \\ $$

Commented by Acem last updated on 09/Nov/22

Good, and it′s better is forming a tree like this:

$${Good},\:{and}\:{it}'{s}\:{better}\:{is}\:{forming}\:{a}\:{tree}\:{like}\:{this}: \\ $$$$ \\ $$

Commented by Acem last updated on 09/Nov/22

Commented by Acem last updated on 09/Nov/22

But what if the group S had items bigger than 4?   like 6, 7,..., 10 numbers.   Or the numbers were of 9 digits?   Even the tree method would be complex   well try to find other way to solve it  :)

$${But}\:{what}\:{if}\:{the}\:{group}\:{S}\:{had}\:{items}\:{bigger}\:{than}\:\mathrm{4}? \\ $$$$\:{like}\:\mathrm{6},\:\mathrm{7},...,\:\mathrm{10}\:{numbers}. \\ $$$$\:{Or}\:{the}\:{numbers}\:{were}\:{of}\:\mathrm{9}\:{digits}? \\ $$$$\:{Even}\:{the}\:{tree}\:{method}\:{would}\:{be}\:{complex} \\ $$$$\left.\:{well}\:{try}\:{to}\:{find}\:{other}\:{way}\:{to}\:{solve}\:{it}\:\::\right) \\ $$$$\: \\ $$

Commented by Acem last updated on 09/Nov/22

 Note: A new question has been added

$$\:{Note}:\:{A}\:{new}\:{question}\:{has}\:{been}\:{added} \\ $$

Answered by Rasheed.Sindhi last updated on 09/Nov/22

B)    abc^(−)         a=3 or 4: 2 ways        b:                  4 ways        c:                  4 ways  Total ways    2∙4∙4=32

$$\left.\boldsymbol{{B}}\right)\:\:\:\:\overline {{abc}} \\ $$$$\:\:\:\:\:\:{a}=\mathrm{3}\:{or}\:\mathrm{4}:\:\mathrm{2}\:{ways} \\ $$$$\:\:\:\:\:\:{b}:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{4}\:{ways} \\ $$$$\:\:\:\:\:\:{c}:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{4}\:{ways} \\ $$$$\mathcal{T}{otal}\:{ways}\:\:\:\:\mathrm{2}\centerdot\mathrm{4}\centerdot\mathrm{4}=\mathrm{32}\: \\ $$

Commented by Acem last updated on 09/Nov/22

Sorry ):  try again...you will do it!

$$\left.{Sorry}\:\right):\:\:{try}\:{again}...{you}\:{will}\:{do}\:{it}! \\ $$

Commented by Acem last updated on 09/Nov/22

 There′s a trap in my 2nd question

$$\:{There}'{s}\:{a}\:{trap}\:{in}\:{my}\:\mathrm{2}{nd}\:{question} \\ $$

Answered by mr W last updated on 09/Nov/22

A)  2×3×2=12 numbers:  342  341  324  321  314  312  432  431  423  421  413  412    B)  assume different digits, then  3−digit numbers: 12 numbers  4−digit numbers: 4!=24 numbers  totally: 36 numbers    if digits may repeat, then we can  form infinite numbers larger than  300.

$$\left.{A}\right) \\ $$$$\mathrm{2}×\mathrm{3}×\mathrm{2}=\mathrm{12}\:{numbers}: \\ $$$$\mathrm{342} \\ $$$$\mathrm{341} \\ $$$$\mathrm{324} \\ $$$$\mathrm{321} \\ $$$$\mathrm{314} \\ $$$$\mathrm{312} \\ $$$$\mathrm{432} \\ $$$$\mathrm{431} \\ $$$$\mathrm{423} \\ $$$$\mathrm{421} \\ $$$$\mathrm{413} \\ $$$$\mathrm{412} \\ $$$$ \\ $$$$\left.{B}\right) \\ $$$${assume}\:{different}\:{digits},\:{then} \\ $$$$\mathrm{3}−{digit}\:{numbers}:\:\mathrm{12}\:{numbers} \\ $$$$\mathrm{4}−{digit}\:{numbers}:\:\mathrm{4}!=\mathrm{24}\:{numbers} \\ $$$${totally}:\:\mathrm{36}\:{numbers} \\ $$$$ \\ $$$${if}\:{digits}\:{may}\:{repeat},\:{then}\:{we}\:{can} \\ $$$${form}\:{infinite}\:{numbers}\:{larger}\:{than} \\ $$$$\mathrm{300}. \\ $$

Commented by JDamian last updated on 09/Nov/22

Mr. W, the question A says *even* numbers.

Commented by mr W last updated on 09/Nov/22

sorry i overlooked that. thanks!

$${sorry}\:{i}\:{overlooked}\:{that}.\:{thanks}! \\ $$

Commented by Acem last updated on 09/Nov/22

Yes Sir! thanks (:

$${Yes}\:{Sir}!\:{thanks}\:\left(:\right. \\ $$

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