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Question Number 180298 by mnjuly1970 last updated on 10/Nov/22

Answered by mr W last updated on 10/Nov/22

Commented by mr W last updated on 10/Nov/22

2β+2γ+120°=180°  ⇒β+γ=30°  α+60°+(90°−β)+(90°−γ)=360°  α−β−γ=120°  ⇒α=120°+30°=150° ✓

$$\mathrm{2}\beta+\mathrm{2}\gamma+\mathrm{120}°=\mathrm{180}° \\ $$$$\Rightarrow\beta+\gamma=\mathrm{30}° \\ $$$$\alpha+\mathrm{60}°+\left(\mathrm{90}°−\beta\right)+\left(\mathrm{90}°−\gamma\right)=\mathrm{360}° \\ $$$$\alpha−\beta−\gamma=\mathrm{120}° \\ $$$$\Rightarrow\alpha=\mathrm{120}°+\mathrm{30}°=\mathrm{150}°\:\checkmark \\ $$

Commented by mnjuly1970 last updated on 10/Nov/22

  thanks alot  sir W

$$\:\:{thanks}\:{alot}\:\:{sir}\:{W} \\ $$

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