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Question Number 180558 by Acem last updated on 13/Nov/22

The football team meets in a circle to consult   about some plan to play, what′s the probability   that the one player of the opponent team who′s   trying to eavesdrops is standing behind the   goalkeeper?

$${The}\:{football}\:{team}\:{meets}\:{in}\:{a}\:{circle}\:{to}\:{consult} \\ $$$$\:{about}\:{some}\:{plan}\:{to}\:{play},\:{what}'{s}\:{the}\:{probability} \\ $$$$\:{that}\:{the}\:{one}\:{player}\:{of}\:{the}\:{opponent}\:{team}\:{who}'{s} \\ $$$$\:{trying}\:{to}\:{eavesdrops}\:{is}\:{standing}\:{behind}\:{the} \\ $$$$\:{goalkeeper}? \\ $$

Answered by Acem last updated on 15/Nov/22

P(A)= ((11×10!)/(11×11!))= (1/(11))

$${P}\left({A}\right)=\:\frac{\mathrm{11}×\mathrm{10}!}{\mathrm{11}×\mathrm{11}!}=\:\frac{\mathrm{1}}{\mathrm{11}} \\ $$

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