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Question Number 18069 by tawa tawa last updated on 14/Jul/17

ai)  If θ is the angle in the fourth quadrant satisfying the equation : cot^2 θ = 4             find the value of the function:  f(θ) = (1/(√5)) (secθ − cosecθ)  aii)  Prove that:   (√((1 + cosθ)/(1 − cosθ)))  =  cosecθ + cotθ,        if  cosθ ≠ 1  (b)   Let  R be a positive real number and let α satisfy the inequality              0 < α < 360. express the function  2sinθ + cosθ in the form  Rsin(θ + α).            Hence, find the value of θ between 0 and 360 which satisfy the equation.              3cosθ + 6sinθ = 1

$$\left.\mathrm{ai}\right)\:\:\mathrm{If}\:\theta\:\mathrm{is}\:\mathrm{the}\:\mathrm{angle}\:\mathrm{in}\:\mathrm{the}\:\mathrm{fourth}\:\mathrm{quadrant}\:\mathrm{satisfying}\:\mathrm{the}\:\mathrm{equation}\::\:\mathrm{cot}^{\mathrm{2}} \theta\:=\:\mathrm{4} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{function}:\:\:\mathrm{f}\left(\theta\right)\:=\:\frac{\mathrm{1}}{\sqrt{\mathrm{5}}}\:\left(\mathrm{sec}\theta\:−\:\mathrm{cosec}\theta\right) \\ $$$$\left.\mathrm{aii}\right)\:\:\mathrm{Prove}\:\mathrm{that}:\:\:\:\sqrt{\frac{\mathrm{1}\:+\:\mathrm{cos}\theta}{\mathrm{1}\:−\:\mathrm{cos}\theta}}\:\:=\:\:\mathrm{cosec}\theta\:+\:\mathrm{cot}\theta,\:\:\:\:\:\:\:\:\mathrm{if}\:\:\mathrm{cos}\theta\:\neq\:\mathrm{1} \\ $$$$\left(\mathrm{b}\right)\:\:\:\mathrm{Let}\:\:\mathrm{R}\:\mathrm{be}\:\mathrm{a}\:\mathrm{positive}\:\mathrm{real}\:\mathrm{number}\:\mathrm{and}\:\mathrm{let}\:\alpha\:\mathrm{satisfy}\:\mathrm{the}\:\mathrm{inequality}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\mathrm{0}\:<\:\alpha\:<\:\mathrm{360}.\:\mathrm{express}\:\mathrm{the}\:\mathrm{function}\:\:\mathrm{2sin}\theta\:+\:\mathrm{cos}\theta\:\mathrm{in}\:\mathrm{the}\:\mathrm{form}\:\:\mathrm{Rsin}\left(\theta\:+\:\alpha\right). \\ $$$$\:\:\:\:\:\:\:\:\:\:\mathrm{Hence},\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\theta\:\mathrm{between}\:\mathrm{0}\:\mathrm{and}\:\mathrm{360}\:\mathrm{which}\:\mathrm{satisfy}\:\mathrm{the}\:\mathrm{equation}. \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{3cos}\theta\:+\:\mathrm{6sin}\theta\:=\:\mathrm{1} \\ $$

Commented by tawa tawa last updated on 15/Jul/17

please help.

$$\mathrm{please}\:\mathrm{help}. \\ $$

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