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Question Number 180718 by a.lgnaoui last updated on 16/Nov/22
Resoudrelesystemedxdt=4x+6ydydt=−3x−5ydzdt=−3x−6y−5z
Answered by mr W last updated on 16/Nov/22
|4−λ6−3−5−λ|=0−(4−λ)(5+λ)+3×6=0(λ+2)(λ−1)=0⇒λ=−2,1V1=[1−1]V2=[2−1]⇒x=c1e−2t+2c2et⇒y=−c1e−2t−c2etdzdt+5z=3c1e−2t⇒z=∫3c1e−2te5tdte5t+c3⇒z=c1e−2t+c3
Commented by a.lgnaoui last updated on 24/Nov/22
thankyouverymuch
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