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Question Number 180954 by Tawa11 last updated on 19/Nov/22

A tugboat is travelling from Asaba to Onitsha across the River Niger with a resultant velocity of 20 knots. If the river flows at 12 knots, the direction of motion of the boat relative to the direction of water flow is?\\n

Answered by mr W last updated on 19/Nov/22

Commented bymr W last updated on 19/Nov/22

θ=180°−tan^(−1) ((20)/(12))=120.96°  v_(Boat) =(√(12^2 +20^2 ))=23.32 kn

$$\theta=\mathrm{180}°−\mathrm{tan}^{−\mathrm{1}} \frac{\mathrm{20}}{\mathrm{12}}=\mathrm{120}.\mathrm{96}° \\ $$ $${v}_{{Boat}} =\sqrt{\mathrm{12}^{\mathrm{2}} +\mathrm{20}^{\mathrm{2}} }=\mathrm{23}.\mathrm{32}\:{kn} \\ $$

Commented byTawa11 last updated on 19/Nov/22

God bless you sir.

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

Commented bymr W last updated on 20/Nov/22

do you think this is correct? it is  only said ♮across the riverε. it doesn′t  mean taking the shortest distance,  or upright to the direction of water  flow. in real life almost nobody does  in this way, as you may have observed  by yourself.  the dotted arrows show what people  in real life do.

$${do}\:{you}\:{think}\:{this}\:{is}\:{correct}?\:{it}\:{is} \\ $$ $${only}\:{said}\:\natural{across}\:{the}\:{river}\varepsilon.\:{it}\:{doesn}'{t} \\ $$ $${mean}\:{taking}\:{the}\:{shortest}\:{distance}, \\ $$ $${or}\:{upright}\:{to}\:{the}\:{direction}\:{of}\:{water} \\ $$ $${flow}.\:{in}\:{real}\:{life}\:{almost}\:{nobody}\:{does} \\ $$ $${in}\:{this}\:{way},\:{as}\:{you}\:{may}\:{have}\:{observed} \\ $$ $${by}\:{yourself}. \\ $$ $${the}\:{dotted}\:{arrows}\:{show}\:{what}\:{people} \\ $$ $${in}\:{real}\:{life}\:{do}. \\ $$

Commented bymr W last updated on 20/Nov/22

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