Solve for x : ((x − a^2 )/(b + c)) + ((x − b^2 )/(c + a)) + ((x − c^2 )/(a + b)) = 4(a + b + c)


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Question Number 181243 by Agnibhoo98 last updated on 23/Nov/22

$Solve for x :$ $\frac{x - a^{2}}{b + c} + \frac{x - b^{2}}{c + a} + \frac{x - c^{2}}{a + b} = 4 (a + b + c)$
	Answered by Frix last updated on 23/Nov/22

	$x = {(a + b + c)}^{2}$ $x - a^{2} = b^{2} + c^{2} + 2 a b + 2 a c + 2 b c =$ $= {(b + c)}^{2} + 2 a b + 2 a c = {(b + c)}^{2} + 2 a (b + c) =$ $= (b + c) (2 a + b + c)$ $the rest is plain to see$
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