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Question Number 181375 by Tawa11 last updated on 24/Nov/22

If  a = 1, b = 2, c = 3, ... z  =  26  then    (t − a)(t − b)(t − c) ... (t − y)(t − z) =   ??

$$\mathrm{If}\:\:\mathrm{a}\:=\:\mathrm{1},\:\mathrm{b}\:=\:\mathrm{2},\:\mathrm{c}\:=\:\mathrm{3},\:...\:\mathrm{z}\:\:=\:\:\mathrm{26} \\ $$$$\mathrm{then}\:\:\:\:\left(\mathrm{t}\:−\:\mathrm{a}\right)\left(\mathrm{t}\:−\:\mathrm{b}\right)\left(\mathrm{t}\:−\:\mathrm{c}\right)\:...\:\left(\mathrm{t}\:−\:\mathrm{y}\right)\left(\mathrm{t}\:−\:\mathrm{z}\right)\:=\:\:\:?? \\ $$

Commented by mr W last updated on 24/Nov/22

 ...  is (t−d)...(t−s)(t−t)(t−u)...(t−x)

$$\:...\:\:{is}\:\left({t}−{d}\right)...\left({t}−{s}\right)\left({t}−{t}\right)\left({t}−{u}\right)...\left({t}−{x}\right) \\ $$

Commented by Tawa11 last updated on 24/Nov/22

Please what is the priciple behind it sir.

$$\mathrm{Please}\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{priciple}\:\mathrm{behind}\:\mathrm{it}\:\mathrm{sir}. \\ $$

Answered by Agnibhoo98 last updated on 24/Nov/22

0

$$\mathrm{0} \\ $$

Commented by Tawa11 last updated on 24/Nov/22

How can I know it is zero sir.

$$\mathrm{How}\:\mathrm{can}\:\mathrm{I}\:\mathrm{know}\:\mathrm{it}\:\mathrm{is}\:\mathrm{zero}\:\mathrm{sir}. \\ $$

Commented by JDamian last updated on 24/Nov/22

read what Mr. W has written: (t-t)=0

Commented by Tawa11 last updated on 24/Nov/22

I understand now sir, God bless you sirs.

$$\mathrm{I}\:\mathrm{understand}\:\mathrm{now}\:\mathrm{sir},\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sirs}. \\ $$

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