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Question Number 181435 by SEKRET last updated on 25/Nov/22

$$\frac{{\mathit{\delta }}^2\mathbf{u}}{\mathit{\delta }{\mathbf{t}}^2}=4\frac{{\mathit{\delta }}^2\mathbf{u}}{\mathit{\delta }{\mathbf{x}}^2};\mathbf{u}{\mid }_{\mathbf{t}=0}=\mathbf{sin}\left(\mathbf{x}\right);\frac{\mathit{\delta }\mathbf{u}}{\mathit{\delta }\mathbf{t}}{\mid }_{\mathbf{t}=0}=\mathbf{x}$$

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