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Question Number 181439 by mnjuly1970 last updated on 25/Nov/22

Answered by mr W last updated on 25/Nov/22

Commented by mr W last updated on 25/Nov/22

$$\left[ABCD\right]=\left[{AB}^{\prime }{D}^{\prime }\right]$$$$=\left[{AB}^{\prime }C\right]+\left[{ACD}^{\prime }\right]$$$$=\frac{d_1\times B^{\prime }C\times \sin \alpha }{2}+\frac{d_1\times {CD}^{\prime }\times \sin (\pi -\alpha )}{2}$$$$=\frac{d_1\times (B^{\prime }C+{CD}^{\prime })\times \sin \alpha }{2}$$$$=\frac{d_1{d}_2\sin \alpha }{2}✓$$

Commented by SEKRET last updated on 26/Nov/22

$$\mathbf{you}\mathbf{always}\mathbf{give}\mathbf{a}\mathbf{very}\mathbf{nice}\mathbf{solution}$$

Commented by mr W last updated on 26/Nov/22

$$thanks!$$

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