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Question Number 181627 by Shrinava last updated on 27/Nov/22

$$\mathrm{Point}\mathrm{E}\mathrm{is}\mathrm{marked}\mathrm{on}\mathrm{side}\mathrm{AD}\mathrm{in}$$$$\mathrm{rhombus}\mathrm{ABCD}.\mathrm{If}\mathrm{AC}=6\sqrt{10}\mathrm{and}$$$$\mathrm{BD}=2\sqrt{10}.\mathrm{How}\mathrm{many}\mathrm{different}$$$$\mathrm{integer}\mathrm{values}\mathrm{can}\mathrm{a}\mathrm{piece}\mathrm{of}\mathrm{BE}\mathrm{take}?$$

Commented by Shrinava last updated on 28/Nov/22

$$\mathrm{Ansser}:$$$$\mathrm{a})2\mathrm{b})3\mathrm{c})4\mathrm{d})6\mathrm{e})7$$

Answered by Acem last updated on 28/Nov/22

$$Eightvalues;BE\in \mathbb{Z},BE=\{11,12,...,18\}$$$$Side=10,Bigdiagonal\approx 18.97$$$$$$

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