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Question Number 181658 by a.lgnaoui last updated on 28/Nov/22

$$AreaofCircle?$$

Commented by a.lgnaoui last updated on 28/Nov/22

Commented by BaliramKumar last updated on 28/Nov/22

Commented by BaliramKumar last updated on 28/Nov/22

$$BF\times FC=EF\times FG$$$$4\times 4=8\times (d-8)$$$$2=d-8$$$$d=10$$$$2r=10$$$$r=5$$$$Area=\pi r^2=25\pi$$$$Secondmethod$$$${OB}^2={OF}^2+{BF}^2$$$$r^2={(8-r)}^2+4^2$$$$r^2=8^2-2\times 8\times r+r^2+16$$$$16r=80$$$$r=5$$$$Area=\pi r^2=\pi \cdot 5^2=25\pi$$$$$$

Commented by a.lgnaoui last updated on 28/Nov/22

$$thankyou$$

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