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Question Number 181673 by cherokeesay last updated on 28/Nov/22

Answered by HeferH last updated on 28/Nov/22

$$A=\frac{(r_1+r_2)BD}{2}$$$$BD=5-(\frac{16}{5}+1)=\frac{25-21}{5}=\frac{4}{5}$$$$A=\frac{1}{2}(2+\frac{12}{5})\frac{4}{5}=\frac{44}{25}{u}^2$$

Commented by cherokeesay last updated on 29/Nov/22

$$Nicesolution,$$$$thankyousir.$$

Answered by a.lgnaoui last updated on 29/Nov/22

$$Area=1,76$$

Answered by a.lgnaoui last updated on 29/Nov/22

Answered by a.lgnaoui last updated on 29/Nov/22

$$\tan \alpha =\frac{3}{4}\alpha =36,87$$$${\mathrm{AE}}^2=2^2+4^2\mathrm{AE}=2\sqrt{5}\Rightarrow \mathrm{DE}=4$$$$\mathrm{EF}=\sqrt{{\mathrm{CE}}^2+{\mathrm{CF}}^2}=\sqrt{16+9}=5$$$$\sin \alpha =\frac{\mathrm{CF}}{\mathrm{EF}}=\frac{3}{5}=\frac{\mathrm{BC}}{\mathrm{CE}}\mathrm{BC}=\frac{12}{5}=2,4$$$${\mathrm{BE}}^2={\mathrm{CE}}^2-{\mathrm{BC}}^2\Rightarrow \mathrm{BE}=3,2$$$$alors\mathrm{BD}=\mathrm{DE}-\mathrm{BE}=0,8$$$$parconsequant:Aire=A_1+A_2$$$$A_1=\frac{1}{2}\left(\mathrm{AD}\times \mathrm{BD}\right)=\frac{2\times 0,8}{2}=0,8$$$${\mathrm{A}}_2=\frac{1}{2}\left(\mathrm{BD}\times \mathrm{BC}\right)=\frac{2,4\times 0,8}{2}=0,96$$$$A=1,76$$$$$$

Commented by cherokeesay last updated on 29/Nov/22

$$Nice!$$$$thankyousomuch.$$

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