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Question Number 181699 by Shrinava last updated on 28/Nov/22
Proveitbymathematicalinduction:∣∑nj=1xj∣⩽∑nj=1sinxj;xj∈[0,π]
Commented by mr W last updated on 28/Nov/22
whatifxj=π2?LHS=n×π2RHS=n×1=nLHS>RHS!⇒questioniswrong!
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