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Question Number 182253 by Tawa11 last updated on 06/Dec/22

Commented by Tawa11 last updated on 06/Dec/22

$$\mathrm{Sirs},\mathrm{see}\mathrm{whag}\mathrm{I}\mathrm{did}.$$$$\mathrm{h}=5+30\mathrm{t}-{5\mathrm{t}}^2$$$${\mathrm{h}}^{\prime }=30-10\mathrm{t}$$$$10\mathrm{t}=30$$$$\mathrm{t}=\frac{30}{10}$$$$\mathrm{t}=3\sec .$$$$$$$$\mathrm{Am}\mathrm{I}\mathrm{correct}???$$

Commented by akacad last updated on 06/Dec/22

$$maximumheightis50meter.putting$$$$t=3inthegivenequationforh.$$$$velocityafter2secondsisgivenby\frac{dh}{dt}$$$$=30-10t.puttingt=2itcomes10m/s$$

Commented by Tawa11 last updated on 07/Dec/22

$$\mathrm{I}\mathrm{understand},\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}.$$

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