Question and Answers Forum

All Questions      Topic List

Limits Questions

Previous in All Question      Next in All Question      

Previous in Limits      Next in Limits      

Question Number 182346 by cortano1 last updated on 08/Dec/22

Commented by SANOGO last updated on 08/Dec/22

thank you

$${thank}\:{you} \\ $$

Answered by CrispyXYZ last updated on 08/Dec/22

=lim_(x→1) ((((3π)/x^2 ) sin(((3π)/x)))/((π/2) cos(((πx)/2))))  =lim_(x→1) ((−((3π)/x^4 )(2x sin(((3π)/x))+3π cos(((3π)/x))))/(−(π^2 /4) sin(((πx)/2))))  =((−3π ∙ (−3π))/(−(π^2 /4)))  =−36

$$=\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\frac{\frac{\mathrm{3}\pi}{{x}^{\mathrm{2}} }\:\mathrm{sin}\left(\frac{\mathrm{3}\pi}{{x}}\right)}{\frac{\pi}{\mathrm{2}}\:\mathrm{cos}\left(\frac{\pi{x}}{\mathrm{2}}\right)} \\ $$$$=\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\frac{−\frac{\mathrm{3}\pi}{{x}^{\mathrm{4}} }\left(\mathrm{2}{x}\:\mathrm{sin}\left(\frac{\mathrm{3}\pi}{{x}}\right)+\mathrm{3}\pi\:\mathrm{cos}\left(\frac{\mathrm{3}\pi}{{x}}\right)\right)}{−\frac{\pi^{\mathrm{2}} }{\mathrm{4}}\:\mathrm{sin}\left(\frac{\pi{x}}{\mathrm{2}}\right)} \\ $$$$=\frac{−\mathrm{3}\pi\:\centerdot\:\left(−\mathrm{3}\pi\right)}{−\frac{\pi^{\mathrm{2}} }{\mathrm{4}}} \\ $$$$=−\mathrm{36} \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com