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Question Number 182623 by Acem last updated on 12/Dec/22

Commented by Acem last updated on 12/Dec/22

Find x°

$$\:{Find}\:{x}° \\ $$

Answered by HeferH last updated on 12/Dec/22

Commented by Acem last updated on 12/Dec/22

Thanks freind!

$${Thanks}\:{freind}! \\ $$

Commented by manxsol last updated on 12/Dec/22

Sir HeferH, how building polygon

$${Sir}\:{HeferH},\:{how}\:{building}\:{polygon} \\ $$

Commented by Acem last updated on 12/Dec/22

Commented by Acem last updated on 12/Dec/22

Our friend codes his solutions :D

$${Our}\:{friend}\:{codes}\:{his}\:{solutions}\:\:\::{D} \\ $$

Commented by Acem last updated on 12/Dec/22

△ ACD we found that x= 60− 2α & after mirror we found that x= 2α^(According to the polyg.) ⇒ α= 15° hence x= 30°

$$\bigtriangleup\:{ACD}\:{we}\:{found}\:{that}\:{x}=\:\mathrm{60}−\:\mathrm{2}\alpha \\ $$$$\:\&\:{after}\:{mirror}\:{we}\:{found}\:{that}\:{x}=\:\mathrm{2}\alpha\:^{{According}\:{to}\:{the}\:{polyg}.} \\ $$$$\:\Rightarrow\:\alpha=\:\mathrm{15}°\:\:{hence}\:{x}=\:\mathrm{30}° \\ $$$$ \\ $$

Commented by manxsol last updated on 12/Dec/22

thanks ,my geometry is hard.

$${thanks}\:,{my}\:{geometry}\:{is}\:{hard}. \\ $$$$ \\ $$

Commented by Acem last updated on 12/Dec/22

It will be easy inshaAllah, just go deep & pull things apart!

$${It}\:{will}\:{be}\:{easy}\:{inshaAllah},\:{just}\:{go}\:{deep} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\& \\ $$$$\:\:\:\:\:\:{pull}\:{things}\:{apart}! \\ $$$$ \\ $$

Answered by manxsol last updated on 12/Dec/22

Commented by manxsol last updated on 12/Dec/22

Saludos,Sir Acem

$${Saludos},{Sir}\:{Acem} \\ $$

Commented by Acem last updated on 12/Dec/22

Saludos y aprecio por tu clase y hermosa persona!

$${Saludos}\:{y}\:{aprecio}\:{por}\:{tu}\:{clase}\:{y}\:{hermosa}\:{persona}! \\ $$

Commented by Acem last updated on 12/Dec/22

Oh my friend, so you′re going to make me dizzy while am spinning on a circle of radius 1 ):

$${Oh}\:{my}\:{friend},\:{so}\:{you}'{re}\:{going}\:{to}\:{make}\:{me}\:{dizzy} \\ $$$$\left.\:{while}\:{am}\:{spinning}\:{on}\:{a}\:{circle}\:{of}\:{radius}\:\mathrm{1}\:\:\right): \\ $$$$ \\ $$

Commented by manxsol last updated on 12/Dec/22

My favorite equation is (ω)^2 +(αςεm)^2 =1

$${My}\:{favorite}\:{equation}\:{is} \\ $$$$\:\:\:\left(\omega\right)^{\mathrm{2}} +\left(\alpha\varsigma\epsilon{m}\right)^{\mathrm{2}} =\mathrm{1} \\ $$

Commented by Acem last updated on 12/Dec/22

You′re a wicked man more than our friend, so you′re going to spin us in that circle till dizzy (: Oh, but why our friend removed his comment ): i just kidding with him (:

$$\:{You}'{re}\:{a}\:{wicked}\:{man}\:{more}\:{than}\:{our}\:{friend},\:{so} \\ $$$$\:{you}'{re}\:{going}\:{to}\:{spin}\:{us}\:{in}\:\:{that}\:{circle}\:{till}\:{dizzy}\:\left(:\right. \\ $$$$\left.\:{Oh},\:{but}\:{why}\:{our}\:{friend}\:{removed}\:{his}\:{comment}\:\right): \\ $$$$\:{i}\:{just}\:{kidding}\:{with}\:{him}\:\left(:\right. \\ $$

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