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Question Number 182675 by Acem last updated on 12/Dec/22

	Answered by HeferH last updated on 12/Dec/22

	$64 ?$
	Commented by Acem last updated on 12/Dec/22

	$y e s!$
	Answered by HeferH last updated on 12/Dec/22

	$l e t x b e t h e s i d e o f t h e s q u a r e, y t h e s i d e o f$ $t h e r e c t a n g l e w i t h p e r i m e t e r 25$ $2 x + 2 y = 25$ $2 (x - y) + 2 x = 23$ $\Rightarrow 4 x - 2 y = 23 (+)$ $2 x + 2 y = 25$ $6 x + 0 = 48$ $x = 8$ $A = 64 u^{2}$
	Commented by Acem last updated on 13/Dec/22

	$T h a n k y o u S i r!$
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