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Question Number 182896 by sciencestudent last updated on 16/Dec/22

Commented by JDamian last updated on 16/Dec/22

bigger than what?

Answered by mr W last updated on 17/Dec/22

$$say\mathrm{\angle }B=20°$$$$\underset{―}{case1:}$$$$\sin \mathrm{\angle }A=\frac{\sin 20°}{3}$$$$\Rightarrow \mathrm{\angle }A={\sin }^{-1}\left(\frac{\sin 20°}{3}\right)\approx 6.5°$$$$\underset{―}{case2:}$$$$\sin (180°-20°-A)=3\sin A$$$$\tan A=\frac{\sin 20°}{3-\cos 20°}$$$$\Rightarrow A={\tan }^{-1}\left(\frac{\sin 20°}{3-\cos 20°}\right)\approx 9.4°$$

Commented by mr W last updated on 17/Dec/22

Commented by sciencestudent last updated on 18/Dec/22

$$thankssir!$$

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